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Solving integrals/ tg(x)/(-2*sin(2x)+1)

Integral of tg(x)/(-2*sin(2x)+1) dx

Limits of integration:

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Piecewise:

The solution

You have entered [src] 
  1                   
  /                   
 |                    
 |       tan(x)       
 |  --------------- dx
 |  -2*sin(2*x) + 1   
 |                    
/                     
0
∫01tan⁡(x)1−2sin⁡(2x) dx\int\limits_{0}^{1} \frac{\tan{\left(x \right)}}{1 - 2 \sin{\left(2 x \right)}}\, dx 
Integral(tan(x)/(-2*sin(2*x) + 1), (x, 0, 1))
The answer (Indefinite) [src] 
  /                           /                  
 |                           |                   
 |      tan(x)               |      tan(x)       
 | --------------- dx = C -  | --------------- dx
 | -2*sin(2*x) + 1           | -1 + 2*sin(2*x)   
 |                           |                   
/                           /
∫tan⁡(x)1−2sin⁡(2x) dx=C−∫tan⁡(x)2sin⁡(2x)−1 dx\int \frac{\tan{\left(x \right)}}{1 - 2 \sin{\left(2 x \right)}}\, dx = C - \int \frac{\tan{\left(x \right)}}{2 \sin{\left(2 x \right)} - 1}\, dx
Simplify
The answer [src] 
   1                   
   /                   
  |                    
  |       tan(x)       
- |  --------------- dx
  |  -1 + 2*sin(2*x)   
  |                    
 /                     
 0
−∫01tan⁡(x)2sin⁡(2x)−1 dx- \int\limits_{0}^{1} \frac{\tan{\left(x \right)}}{2 \sin{\left(2 x \right)} - 1}\, dx 
=
= 
   1                   
   /                   
  |                    
  |       tan(x)       
- |  --------------- dx
  |  -1 + 2*sin(2*x)   
  |                    
 /                     
 0
−∫01tan⁡(x)2sin⁡(2x)−1 dx- \int\limits_{0}^{1} \frac{\tan{\left(x \right)}}{2 \sin{\left(2 x \right)} - 1}\, dx 
-Integral(tan(x)/(-1 + 2*sin(2*x)), (x, 0, 1))
Numerical answer [src] 
-0.456377719382342
-0.456377719382342

    Use the examples entering the upper and lower limits of integration.

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