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t^2/(t^2+1)

You entered:

t^2/(t^2+1)

What you mean?

Integral of t^2/(t^2+1) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  1          
  /          
 |           
 |     2     
 |    t      
 |  ------ dt
 |   2       
 |  t  + 1   
 |           
/            
0            
$$\int\limits_{0}^{1} \frac{t^{2}}{t^{2} + 1}\, dt$$
Detail solution
  1. Rewrite the integrand:

  2. Integrate term-by-term:

    1. The integral of a constant is the constant times the variable of integration:

    1. The integral of a constant times a function is the constant times the integral of the function:

      1. The integral of is .

      So, the result is:

    The result is:

  3. Add the constant of integration:


The answer is:

The answer (Indefinite) [src]
  /                           
 |                            
 |    2                       
 |   t                        
 | ------ dt = C + t - atan(t)
 |  2                         
 | t  + 1                     
 |                            
/                             
$$t-\arctan t$$
The graph
The answer [src]
    pi
1 - --
    4 
$$-{{\pi-4}\over{4}}$$
=
=
    pi
1 - --
    4 
$$- \frac{\pi}{4} + 1$$
Numerical answer [src]
0.214601836602552
0.214601836602552
The graph
Integral of t^2/(t^2+1) dx

    Use the examples entering the upper and lower limits of integration.