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Solving integrals/ t^3

Integral of t^3 dx

You have entered [src]

$$\int\limits_{0}^{1} t^{3}\, dt$$

Integral(t^3, (t, 0, 1))

Detail solution

The integral of $t^{n}$ is $\frac{t^{n + 1}}{n + 1}$ when $n \neq -1$ :

$\int t^{3}\, dt = \frac{t^{4}}{4}$
Add the constant of integration:

$\frac{t^{4}}{4}+ \mathrm{constant}$

The answer is:

$\frac{t^{4}}{4}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /              
 |              4
 |  3          t 
 | t  dt = C + --
 |             4 
/

$$\int t^{3}\, dt = C + \frac{t^{4}}{4}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

1/4

$$\frac{1}{4}$$

1/4

$$\frac{1}{4}$$

1/4

Numerical answer [src]

0.25

0.25

The graph

Use the examples entering the upper and lower limits of integration.