积分 t^4 dt

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$$\int\limits_{0}^{1} t^{4}\, dt$$

Integral(t^4, (t, 0, 1))

Detail solution

The integral of $t^{n}$ is $\frac{t^{n + 1}}{n + 1}$ when $n \neq -1$ :

$\int t^{4}\, dt = \frac{t^{5}}{5}$
Add the constant of integration:

$\frac{t^{5}}{5}+ \mathrm{constant}$

The answer is:

$\frac{t^{5}}{5}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /              
 |              5
 |  4          t 
 | t  dt = C + --
 |             5 
/

$$\int t^{4}\, dt = C + \frac{t^{5}}{5}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

1/5

$$\frac{1}{5}$$

1/5

$$\frac{1}{5}$$

1/5

Numerical answer [src]

0.2

0.2

图像

这些示例也可用于输入定积分的上下限.