Integral of t^2ln(x)dt dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫t2log(x)dt=log(x)∫t2dt
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The integral of tn is n+1tn+1 when n=−1:
∫t2dt=3t3
So, the result is: 3t3log(x)
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Add the constant of integration:
3t3log(x)+constant
The answer is:
3t3log(x)+constant
The answer (Indefinite)
[src]
/
| 3
| 2 t *log(x)
| t *log(x) dt = C + ---------
| 3
/
∫t2log(x)dt=C+3t3log(x)
3log(x)
=
3log(x)
Use the examples entering the upper and lower limits of integration.