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- Improper integral
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How to use it?
- Integral of d{x}:
- Integral of sin(log2(x))/x
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Integral of 3x^2-5
- Integral of sqrt(x^2+2x^4)
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Integral of sh(2x)
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Identical expressions
- sqrt(x^ two +2x^ four)
- square root of (x squared plus 2x to the power of 4)
- square root of (x to the power of two plus 2x to the power of four)
- √(x^2+2x^4)
- sqrt(x2+2x4)
- sqrtx2+2x4
- sqrt(x²+2x⁴)
- sqrt(x to the power of 2+2x to the power of 4)
- sqrtx^2+2x^4
- sqrt(x^2+2x^4)dx
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Similar expressions
- sqrt(x^2-2x^4)
Integral of sqrt(x^2+2x^4) dx
The solution
You have entered
[src]
1 / | | ___________ | / 2 4 | \/ x + 2*x dx | / 0
$$\int\limits_{0}^{1} \sqrt{2 x^{4} + x^{2}}\, dx$$
Integral(sqrt(x^2 + 2*x^4), (x, 0, 1))
The answer
[src]
___ 1 \/ 3 - - + ----- 6 2
$${{\sqrt{3}}\over{2}}-{{1}\over{6}}$$
=
=
___ 1 \/ 3 - - + ----- 6 2
$$- \frac{1}{6} + \frac{\sqrt{3}}{2}$$
Use the examples entering the upper and lower limits of integration.