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Integral of sqrt(x^2-x-6) dx

Limits of integration:

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The solution

You have entered [src]
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$$\int\limits_{0}^{1} \sqrt{\left(x^{2} - x\right) - 6}\, dx$$
Integral(sqrt(x^2 - x - 6), (x, 0, 1))
The answer [src]
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$$\int\limits_{0}^{1} \sqrt{x - 3} \sqrt{x + 2}\, dx$$
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$$\int\limits_{0}^{1} \sqrt{x - 3} \sqrt{x + 2}\, dx$$
Integral(sqrt(-3 + x)*sqrt(2 + x), (x, 0, 1))
Numerical answer [src]
(0.0 + 2.48323187633116j)
(0.0 + 2.48323187633116j)

    Use the examples entering the upper and lower limits of integration.