Integral of sqrt(x+1) dx
The solution
Detail solution
-
Let u=x+1.
Then let du=dx and substitute du:
∫udu
-
The integral of un is n+1un+1 when n=−1:
∫udu=32u23
Now substitute u back in:
32(x+1)23
-
Now simplify:
32(x+1)23
-
Add the constant of integration:
32(x+1)23+constant
The answer is:
32(x+1)23+constant
The answer (Indefinite)
[src]
/
| 3/2
| _______ 2*(x + 1)
| \/ x + 1 dx = C + ------------
| 3
/
∫x+1dx=C+32(x+1)23
The graph
___
2 4*\/ 2
- - + -------
3 3
−32+342
=
___
2 4*\/ 2
- - + -------
3 3
−32+342
Use the examples entering the upper and lower limits of integration.