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How to use it?
- Integral of d{x}:
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Integral of x/(3x²-1)^4
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Integral of sin(x²)
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Integral of du
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Integral of √(9-x^2)
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Identical expressions
- sqrt(two 4x^2+12x-4x^ three)
- square root of (24x squared plus 12x minus 4x cubed )
- square root of (two 4x squared plus 12x minus 4x to the power of three)
- √(24x^2+12x-4x^3)
- sqrt(24x2+12x-4x3)
- sqrt24x2+12x-4x3
- sqrt(24x²+12x-4x³)
- sqrt(24x to the power of 2+12x-4x to the power of 3)
- sqrt24x^2+12x-4x^3
- sqrt(24x^2+12x-4x^3)dx
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Similar expressions
- sqrt(24x^2-12x-4x^3)
- sqrt(24x^2+12x+4x^3)
Integral of sqrt(24x^2+12x-4x^3) dx
The solution
You have entered
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1 / | | _____________________ | / 2 3 | \/ 24*x + 12*x - 4*x dx | / 0
$$\int\limits_{0}^{1} \sqrt{- 4 x^{3} + \left(24 x^{2} + 12 x\right)}\, dx$$
Integral(sqrt(24*x^2 + 12*x - 4*x^3), (x, 0, 1))
The answer (Indefinite)
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/ / | | | _____________________ | ___________________ | / 2 3 | / 3 2 | \/ 24*x + 12*x - 4*x dx = C + 2* | \/ - x + 3*x + 6*x dx | | / /
$$\int \sqrt{- 4 x^{3} + \left(24 x^{2} + 12 x\right)}\, dx = C + 2 \int \sqrt{- x^{3} + 6 x^{2} + 3 x}\, dx$$
The answer
[src]
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2* | \/ x *\/ 3 - x + 6*x dx
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$$2 \int\limits_{0}^{1} \sqrt{x} \sqrt{- x^{2} + 6 x + 3}\, dx$$
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2* | \/ x *\/ 3 - x + 6*x dx
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$$2 \int\limits_{0}^{1} \sqrt{x} \sqrt{- x^{2} + 6 x + 3}\, dx$$
2*Integral(sqrt(x)*sqrt(3 - x^2 + 6*x), (x, 0, 1))
Use the examples entering the upper and lower limits of integration.