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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 4x³
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Integral of 8-2x^2
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Integral of (x^2+7x-5)cos2x
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Integral of sin^43x
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Identical expressions
- sqrt(one +(one -sinx)^ two)
- square root of (1 plus (1 minus sinus of x) squared )
- square root of (one plus (one minus sinus of x) to the power of two)
- √(1+(1-sinx)^2)
- sqrt(1+(1-sinx)2)
- sqrt1+1-sinx2
- sqrt(1+(1-sinx)²)
- sqrt(1+(1-sinx) to the power of 2)
- sqrt1+1-sinx^2
- sqrt(1+(1-sinx)^2)dx
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Similar expressions
- sqrt(1-(1-sinx)^2)
- sqrt(1+(1+sinx)^2)
Integral of sqrt(1+(1-sinx)^2) dx
The solution
You have entered
[src]
pi -- 2 / | | ___________________ | / 2 | \/ 1 + (1 - sin(x)) dx | / 0
$$\int\limits_{0}^{\frac{\pi}{2}} \sqrt{\left(1 - \sin{\left(x \right)}\right)^{2} + 1}\, dx$$
Integral(sqrt(1 + (1 - sin(x))^2), (x, 0, pi/2))
The answer
[src]
pi -- 2 / | | ___________________ | / 2 | \/ 1 + (1 - sin(x)) dx | / 0
$$\int\limits_{0}^{\frac{\pi}{2}} \sqrt{\left(1 - \sin{\left(x \right)}\right)^{2} + 1}\, dx$$
=
=
pi -- 2 / | | ___________________ | / 2 | \/ 1 + (1 - sin(x)) dx | / 0
$$\int\limits_{0}^{\frac{\pi}{2}} \sqrt{\left(1 - \sin{\left(x \right)}\right)^{2} + 1}\, dx$$
Integral(sqrt(1 + (1 - sin(x))^2), (x, 0, pi/2))
Use the examples entering the upper and lower limits of integration.