Mister Exam

Lang:

Other calculators

How to use it?
Integral of d{x}:
Integral of xe
Integral of 3x²
Integral of e^-t
Integral of e^(x*y)
Identical expressions
sinx-sin^ three x/3
sinus of x minus sinus of cubed x divide by 3
sinus of x minus sinus of to the power of three x divide by 3
sinx-sin3x/3
sinx-sin³x/3
sinx-sin to the power of 3x/3
sinx-sin^3x divide by 3
sinx-sin^3x/3dx
Similar expressions
sinx+sin^3x/3

Integral of sinx-sin^3x/3 dx

The solution

You have entered [src]

  1                      
  /                      
 |                       
 |  /            3   \   
 |  |         sin (x)|   
 |  |sin(x) - -------| dx
 |  \            3   /   
 |                       
/                        
0

$$\int\limits_{0}^{1} \left(- \frac{\sin^{3}{\left(x \right)}}{3} + \sin{\left(x \right)}\right)\, dx$$

Integral(sin(x) - sin(x)^3/3, (x, 0, 1))

Detail solution

Integrate term-by-term:
1. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int \left(- \frac{\sin^{3}{\left(x \right)}}{3}\right)\, dx = - \frac{\int \sin^{3}{\left(x \right)}\, dx}{3}$
  1. Rewrite the integrand:
    
    $\sin^{3}{\left(x \right)} = \left(1 - \cos^{2}{\left(x \right)}\right) \sin{\left(x \right)}$
  2. There are multiple ways to do this integral.
    Method #1
    1. Let $u = \cos{\left(x \right)}$ .
      
      Then let $du = - \sin{\left(x \right)} dx$ and substitute $du$ :
      
      $\int \left(u^{2} - 1\right)\, du$
      
      Integrate term-by-term:
      
      The integral of $u^{n}$ is $\frac{u^{n + 1}}{n + 1}$ when $n \neq -1$ :
      
      $\int u^{2}\, du = \frac{u^{3}}{3}$
      
      The integral of a constant is the constant times the variable of integration:
      
      $\int \left(-1\right)\, du = - u$
      
      The result is: $\frac{u^{3}}{3} - u$
      
      Now substitute $u$ back in:
      
      $\frac{\cos^{3}{\left(x \right)}}{3} - \cos{\left(x \right)}$
    Method #2
    1. Rewrite the integrand:
      
      $\left(1 - \cos^{2}{\left(x \right)}\right) \sin{\left(x \right)} = - \sin{\left(x \right)} \cos^{2}{\left(x \right)} + \sin{\left(x \right)}$
    2. Integrate term-by-term:
      
      The integral of a constant times a function is the constant times the integral of the function:
      
      $\int \left(- \sin{\left(x \right)} \cos^{2}{\left(x \right)}\right)\, dx = - \int \sin{\left(x \right)} \cos^{2}{\left(x \right)}\, dx$
      
      Let $u = \cos{\left(x \right)}$ .
      
      Then let $du = - \sin{\left(x \right)} dx$ and substitute $- du$ :
      
      $\int \left(- u^{2}\right)\, du$
      
      The integral of a constant times a function is the constant times the integral of the function:
      
      $\int u^{2}\, du = - \int u^{2}\, du$
      
      The integral of $u^{n}$ is $\frac{u^{n + 1}}{n + 1}$ when $n \neq -1$ :
      
      $\int u^{2}\, du = \frac{u^{3}}{3}$
      
      So, the result is: $- \frac{u^{3}}{3}$
      
      Now substitute $u$ back in:
      
      $- \frac{\cos^{3}{\left(x \right)}}{3}$
      
      So, the result is: $\frac{\cos^{3}{\left(x \right)}}{3}$
      
      The integral of sine is negative cosine:
      
      $\int \sin{\left(x \right)}\, dx = - \cos{\left(x \right)}$
      
      The result is: $\frac{\cos^{3}{\left(x \right)}}{3} - \cos{\left(x \right)}$
    Method #3
    1. Rewrite the integrand:
      
      $\left(1 - \cos^{2}{\left(x \right)}\right) \sin{\left(x \right)} = - \sin{\left(x \right)} \cos^{2}{\left(x \right)} + \sin{\left(x \right)}$
    2. Integrate term-by-term:
      
      The integral of a constant times a function is the constant times the integral of the function:
      
      $\int \left(- \sin{\left(x \right)} \cos^{2}{\left(x \right)}\right)\, dx = - \int \sin{\left(x \right)} \cos^{2}{\left(x \right)}\, dx$
      
      Let $u = \cos{\left(x \right)}$ .
      
      Then let $du = - \sin{\left(x \right)} dx$ and substitute $- du$ :
      
      $\int \left(- u^{2}\right)\, du$
      
      The integral of a constant times a function is the constant times the integral of the function:
      
      $\int u^{2}\, du = - \int u^{2}\, du$
      
      The integral of $u^{n}$ is $\frac{u^{n + 1}}{n + 1}$ when $n \neq -1$ :
      
      $\int u^{2}\, du = \frac{u^{3}}{3}$
      
      So, the result is: $- \frac{u^{3}}{3}$
      
      Now substitute $u$ back in:
      
      $- \frac{\cos^{3}{\left(x \right)}}{3}$
      
      So, the result is: $\frac{\cos^{3}{\left(x \right)}}{3}$
      
      The integral of sine is negative cosine:
      
      $\int \sin{\left(x \right)}\, dx = - \cos{\left(x \right)}$
      
      The result is: $\frac{\cos^{3}{\left(x \right)}}{3} - \cos{\left(x \right)}$
  So, the result is: $- \frac{\cos^{3}{\left(x \right)}}{9} + \frac{\cos{\left(x \right)}}{3}$
1. The integral of sine is negative cosine:
  
  $\int \sin{\left(x \right)}\, dx = - \cos{\left(x \right)}$
The result is: $- \frac{\cos^{3}{\left(x \right)}}{9} - \frac{2 \cos{\left(x \right)}}{3}$
Now simplify:

$- \frac{\left(\cos^{2}{\left(x \right)} + 6\right) \cos{\left(x \right)}}{9}$
Add the constant of integration:

$- \frac{\left(\cos^{2}{\left(x \right)} + 6\right) \cos{\left(x \right)}}{9}+ \mathrm{constant}$

The answer is:

$- \frac{\left(\cos^{2}{\left(x \right)} + 6\right) \cos{\left(x \right)}}{9}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                              
 |                                               
 | /            3   \                        3   
 | |         sin (x)|          2*cos(x)   cos (x)
 | |sin(x) - -------| dx = C - -------- - -------
 | \            3   /             3          9   
 |                                               
/

$$\int \left(- \frac{\sin^{3}{\left(x \right)}}{3} + \sin{\left(x \right)}\right)\, dx = C - \frac{\cos^{3}{\left(x \right)}}{9} - \frac{2 \cos{\left(x \right)}}{3}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

                  3   
7   2*cos(1)   cos (1)
- - -------- - -------
9      3          9

$$- \frac{2 \cos{\left(1 \right)}}{3} - \frac{\cos^{3}{\left(1 \right)}}{9} + \frac{7}{9}$$

                  3   
7   2*cos(1)   cos (1)
- - -------- - -------
9      3          9

$$- \frac{2 \cos{\left(1 \right)}}{3} - \frac{\cos^{3}{\left(1 \right)}}{9} + \frac{7}{9}$$

7/9 - 2*cos(1)/3 - cos(1)^3/9

Numerical answer [src]

0.400050839948908

0.400050839948908

Use the examples entering the upper and lower limits of integration.

Other calculators

How to use it?

Identical expressions

Similar expressions

Integral of sinx-sin^3x/3 dx

Limits of integration:

The graph:

Piecewise:

The solution

Method #1

Method #2

Method #3