Integral of sinx/x^2 dx
The solution
The answer (Indefinite)
[src]
/ /
| |
| sin(x) | sin(x)
| ------ dx = C + | ------ dx
| 2 | 2
| x | x
| |
/ /
2Γ(−1,ix)+Γ(−1,−ix)
1 - EulerGamma - sin(1) + Ci(1)
∫01x2sinxdx
=
1 - EulerGamma - sin(1) + Ci(1)
−sin(1)−γ+Ci(1)+1
Use the examples entering the upper and lower limits of integration.