Integral of sinx/(sin2xcosx) dx
The solution
Detail solution
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Rewrite the integrand:
sin(2x)cos(x)sin(x)=2cos2(x)1
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The integral of a constant times a function is the constant times the integral of the function:
∫2cos2(x)1dx=2∫cos2(x)1dx
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Don't know the steps in finding this integral.
But the integral is
cos(x)sin(x)
So, the result is: 2cos(x)sin(x)
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Now simplify:
2tan(x)
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Add the constant of integration:
2tan(x)+constant
The answer is:
2tan(x)+constant
The answer (Indefinite)
[src]
/
|
| sin(x) sin(x)
| --------------- dx = C + --------
| sin(2*x)*cos(x) 2*cos(x)
|
/
∫sin(2x)cos(x)sin(x)dx=C+2cos(x)sin(x)
The graph
2cos(1)sin(1)
=
2cos(1)sin(1)
Use the examples entering the upper and lower limits of integration.