Integral of sinxcos^2xdx dx
The solution
Detail solution
-
Let u=cos(x).
Then let du=−sin(x)dx and substitute −du:
∫(−u2)du
-
The integral of a constant times a function is the constant times the integral of the function:
∫u2du=−∫u2du
-
The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: −3u3
Now substitute u back in:
−3cos3(x)
-
Add the constant of integration:
−3cos3(x)+constant
The answer is:
−3cos3(x)+constant
The answer (Indefinite)
[src]
/
| 3
| 2 cos (x)
| sin(x)*cos (x) dx = C - -------
| 3
/
∫sin(x)cos2(x)dx=C−3cos3(x)
The graph
3
1 cos (1)
- - -------
3 3
31−3cos3(1)
=
3
1 cos (1)
- - -------
3 3
31−3cos3(1)
Use the examples entering the upper and lower limits of integration.