Integral of sin^30x*cosx dx
The solution
Detail solution
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Let u=sin(x).
Then let du=cos(x)dx and substitute du:
∫u30du
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The integral of un is n+1un+1 when n=−1:
∫u30du=31u31
Now substitute u back in:
31sin31(x)
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Add the constant of integration:
31sin31(x)+constant
The answer is:
31sin31(x)+constant
The answer (Indefinite)
[src]
/
| 31
| 30 sin (x)
| sin (x)*cos(x) dx = C + --------
| 31
/
∫sin30(x)cos(x)dx=C+31sin31(x)
The graph
Use the examples entering the upper and lower limits of integration.