Integral of (7*sin^3x+5)/sin^2x dx
The solution
Detail solution
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Rewrite the integrand:
sin2(x)7sin3(x)+5=sin2(x)7sin3(x)+sin2(x)5
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫sin2(x)7sin3(x)dx=7∫sin2(x)sin3(x)dx
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Don't know the steps in finding this integral.
But the integral is
−cos(x)
So, the result is: −7cos(x)
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The integral of a constant times a function is the constant times the integral of the function:
∫sin2(x)5dx=5∫sin2(x)1dx
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Don't know the steps in finding this integral.
But the integral is
−sin(x)cos(x)
So, the result is: −sin(x)5cos(x)
The result is: −7cos(x)−sin(x)5cos(x)
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Now simplify:
−tan(x)7sin(x)+5
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Add the constant of integration:
−tan(x)7sin(x)+5+constant
The answer is:
−tan(x)7sin(x)+5+constant
The answer (Indefinite)
[src]
/
|
| 3
| 7*sin (x) + 5 5*cos(x)
| ------------- dx = C - 7*cos(x) - --------
| 2 sin(x)
| sin (x)
|
/
∫sin2(x)7sin3(x)+5dx=C−7cos(x)−sin(x)5cos(x)
The graph
Use the examples entering the upper and lower limits of integration.