Integral of secx dx
The solution
Detail solution
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Rewrite the integrand:
sec(x)=tan(x)+sec(x)tan(x)sec(x)+sec2(x)
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Let u=tan(x)+sec(x).
Then let du=(tan2(x)+tan(x)sec(x)+1)dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(tan(x)+sec(x))
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Add the constant of integration:
log(tan(x)+sec(x))+constant
The answer is:
log(tan(x)+sec(x))+constant
The answer (Indefinite)
[src]
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| sec(x) dx = C + log(sec(x) + tan(x))
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∫sec(x)dx=C+log(tan(x)+sec(x))
The graph
log(1 + sin(1)) log(1 - sin(1))
--------------- - ---------------
2 2
2log(sin(1)+1)−2log(1−sin(1))
=
log(1 + sin(1)) log(1 - sin(1))
--------------- - ---------------
2 2
2log(sin(1)+1)−2log(1−sin(1))
log(1 + sin(1))/2 - log(1 - sin(1))/2
Use the examples entering the upper and lower limits of integration.