Integral of (1+x)dy dx

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$$\int\limits_{0}^{1} \left(x + 1\right)\, dy$$

Integral(1 + x, (y, 0, 1))

Detail solution

The integral of a constant is the constant times the variable of integration:

$\int \left(x + 1\right)\, dy = y \left(x + 1\right)$
Add the constant of integration:

$y \left(x + 1\right)+ \mathrm{constant}$

The answer is:

$y \left(x + 1\right)+ \mathrm{constant}$

The answer (Indefinite) [src]

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$$\int \left(x + 1\right)\, dy = C + y \left(x + 1\right)$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

1 + x

$$x + 1$$

1 + x

$$x + 1$$

1 + x

Use the examples entering the upper and lower limits of integration.