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- Improper integral
- Double Integral
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How to use it?
- Integral of d{x}:
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Integral of ex^2
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Integral of 1-7*x^2
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Integral of xe^(1-x)
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Integral of -xe^x
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Identical expressions
- one /(x^ two + three *x+ two)
- 1 divide by (x squared plus 3 multiply by x plus 2)
- one divide by (x to the power of two plus three multiply by x plus two)
- 1/(x2+3*x+2)
- 1/x2+3*x+2
- 1/(x²+3*x+2)
- 1/(x to the power of 2+3*x+2)
- 1/(x^2+3x+2)
- 1/(x2+3x+2)
- 1/x2+3x+2
- 1/x^2+3x+2
- 1 divide by (x^2+3*x+2)
- 1/(x^2+3*x+2)dx
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Similar expressions
- 1/(x^2+3*x-2)
- 1/(x^2-3*x+2)
Integral of 1/(x^2+3*x+2) dx
The solution
You have entered
[src]
1 / | | 1 | ------------ dx | 2 | x + 3*x + 2 | / 0
$$\int\limits_{0}^{1} \frac{1}{\left(x^{2} + 3 x\right) + 2}\, dx$$
Integral(1/(x^2 + 3*x + 2), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 | ------------ dx = C - log(4 + 2*x) + log(2 + 2*x) | 2 | x + 3*x + 2 | /
$$\int \frac{1}{\left(x^{2} + 3 x\right) + 2}\, dx = C + \log{\left(2 x + 2 \right)} - \log{\left(2 x + 4 \right)}$$
The graph
The answer
[src]
-log(3) + 2*log(2)
$$- \log{\left(3 \right)} + 2 \log{\left(2 \right)}$$
=
=
-log(3) + 2*log(2)
$$- \log{\left(3 \right)} + 2 \log{\left(2 \right)}$$
-log(3) + 2*log(2)
The graph
Use the examples entering the upper and lower limits of integration.