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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 1/(1+4x^2)
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Integral of (sec(x))^3
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Integral of sec^3
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Integral of x*3^x
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Identical expressions
- one /(√(x^ two - four *x+ eight))
- 1 divide by (√(x squared minus 4 multiply by x plus 8))
- one divide by (√(x to the power of two minus four multiply by x plus eight))
- 1/(√(x2-4*x+8))
- 1/√x2-4*x+8
- 1/(√(x²-4*x+8))
- 1/(√(x to the power of 2-4*x+8))
- 1/(√(x^2-4x+8))
- 1/(√(x2-4x+8))
- 1/√x2-4x+8
- 1/√x^2-4x+8
- 1 divide by (√(x^2-4*x+8))
- 1/(√(x^2-4*x+8))dx
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Similar expressions
- 1/(√(x^2-4*x-8))
- 1/(√(x^2+4*x+8))
Integral of 1/(√(x^2-4*x+8)) dx
The solution
You have entered
[src]
1 / | | 1 | ----------------- dx | ______________ | / 2 | \/ x - 4*x + 8 | / 0
$$\int\limits_{0}^{1} \frac{1}{\sqrt{\left(x^{2} - 4 x\right) + 8}}\, dx$$
Integral(1/(sqrt(x^2 - 4*x + 8)), (x, 0, 1))
The answer
[src]
1 / | | 1 | ----------------- dx | ______________ | / 2 | \/ 8 + x - 4*x | / 0
$$\int\limits_{0}^{1} \frac{1}{\sqrt{x^{2} - 4 x + 8}}\, dx$$
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1 / | | 1 | ----------------- dx | ______________ | / 2 | \/ 8 + x - 4*x | / 0
$$\int\limits_{0}^{1} \frac{1}{\sqrt{x^{2} - 4 x + 8}}\, dx$$
Integral(1/sqrt(8 + x^2 - 4*x), (x, 0, 1))
Use the examples entering the upper and lower limits of integration.