2 / | | 1 | --------- dy | x + y + 1 | / 1
Integral(1/(x + y + 1), (y, 1, 2))
Let .
Then let and substitute :
The integral of is .
Now substitute back in:
Now simplify:
Add the constant of integration:
The answer is:
/ | | 1 | --------- dy = C + log(x + y + 1) | x + y + 1 | /
-log(2 + x) + log(3 + x)
=
-log(2 + x) + log(3 + x)
-log(2 + x) + log(3 + x)
Use the examples entering the upper and lower limits of integration.