Integral of 1/(x+x^(1/3)) dx
The solution
Detail solution
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Let u=3x.
Then let du=3x32dx and substitute 3du:
∫u2+13udu
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The integral of a constant times a function is the constant times the integral of the function:
∫u2+1udu=3∫u2+1udu
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The integral of a constant times a function is the constant times the integral of the function:
∫u2+1udu=2∫u2+12udu
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Let u=u2+1.
Then let du=2udu and substitute 2du:
∫2u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(u2+1)
So, the result is: 2log(u2+1)
So, the result is: 23log(u2+1)
Now substitute u back in:
23log(x32+1)
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Add the constant of integration:
23log(x32+1)+constant
The answer is:
23log(x32+1)+constant
The answer (Indefinite)
[src]
/
| / 2/3\
| 1 3*log\1 + x /
| --------- dx = C + ---------------
| 3 ___ 2
| x + \/ x
|
/
∫3x+x1dx=C+23log(x32+1)
The graph
23log(2)
=
23log(2)
Use the examples entering the upper and lower limits of integration.