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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of x^2/(1+x^3)
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Integral of (4-x^2)^(1/2)
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Integral of x^2/sqrt(4-x^2)
- Integral of x^2/(x-1)
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Identical expressions
- one /(x*√(x+ one))
- 1 divide by (x multiply by √(x plus 1))
- one divide by (x multiply by √(x plus one))
- 1/(x√(x+1))
- 1/x√x+1
- 1 divide by (x*√(x+1))
- 1/(x*√(x+1))dx
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Similar expressions
- 1/(x*√(x-1))
Integral of 1/(x*√(x+1)) dx
The solution
You have entered
[src]
1 / | | 1 | 1*----------- dx | _______ | x*\/ x + 1 | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{x \sqrt{x + 1}}\, dx$$
Integral(1/(x*sqrt(x + 1)), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 / _______\ / _______\ | 1*----------- dx = C - log\1 + \/ 1 + x / + log\-1 + \/ 1 + x / | _______ | x*\/ x + 1 | /
$$\log \left(\sqrt{x+1}-1\right)-\log \left(\sqrt{x+1}+1\right)$$
The answer
[src]
1 / | | 1 | ----------- dx | _______ | x*\/ 1 + x | / 0
$${\it \%a}$$
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1 / | | 1 | ----------- dx | _______ | x*\/ 1 + x | / 0
$$\int\limits_{0}^{1} \frac{1}{x \sqrt{x + 1}}\, dx$$
Use the examples entering the upper and lower limits of integration.