Integral of 1/(x-2) dx
The solution
Detail solution
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Let u=x−2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
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Now simplify:
log(x−2)
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Add the constant of integration:
log(x−2)+constant
The answer is:
log(x−2)+constant
The answer (Indefinite)
[src]
/
|
| 1
| 1*----- dx = C + log(x - 2)
| x - 2
|
/
log(x−2)
The graph
=
−log(2)
Use the examples entering the upper and lower limits of integration.