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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 1/sqrt(1+u^2)
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Integral of x*sin2x
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Integral of (1/x^2)dx
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Integral of -x^3
- Derivative of:
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1/(x-1)^2
- How do you in partial fractions?:
- 1/(x-1)^2
- Equation:
- 1/(x-1)^2
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Identical expressions
- one /(x- one)^ two
- 1 divide by (x minus 1) squared
- one divide by (x minus one) to the power of two
- 1/(x-1)2
- 1/x-12
- 1/(x-1)²
- 1/(x-1) to the power of 2
- 1/x-1^2
- 1 divide by (x-1)^2
- 1/(x-1)^2dx
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Similar expressions
- 1/(x+1)^2
Integral of 1/(x-1)^2 dx
The solution
You have entered
[src]
1 / | | 1 | -------- dx | 2 | (x - 1) | / 0
$$\int\limits_{0}^{1} \frac{1}{\left(x - 1\right)^{2}}\, dx$$
Integral(1/((x - 1)^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 1 | -------- dx = C - ------ | 2 -1 + x | (x - 1) | /
$$\int \frac{1}{\left(x - 1\right)^{2}}\, dx = C - \frac{1}{x - 1}$$
The graph
The graph
Use the examples entering the upper and lower limits of integration.