Integral of 1/(sin(x+y^2)) dx
The solution
The answer (Indefinite)
[src]
/
| / / 2\\
| 1 | |x y ||
| ----------- dx = C + log|tan|- + --||
| / 2\ \ \2 2 //
| sin\x + y /
|
/
∫sin(x+y2)1dx=C+log(tan(2x+2y2))
/ / 2\\ / / 2\\
| |y || | |1 y ||
- log|tan|--|| + log|tan|- + --||
\ \2 // \ \2 2 //
−log(tan(2y2))+log(tan(2y2+21))
=
/ / 2\\ / / 2\\
| |y || | |1 y ||
- log|tan|--|| + log|tan|- + --||
\ \2 // \ \2 2 //
−log(tan(2y2))+log(tan(2y2+21))
-log(tan(y^2/2)) + log(tan(1/2 + y^2/2))
Use the examples entering the upper and lower limits of integration.