Integral of 1/(1+exp(y)) dx
The solution
The answer (Indefinite)
[src]
/
|
| 1 / -y\
| ------ dy = C - log\1 + e /
| y
| 1 + e
|
/
∫ey+11dy=C−log(1+e−y)
The graph
−log(1+e)+log(2)+1
=
−log(1+e)+log(2)+1
Use the examples entering the upper and lower limits of integration.