1 / | | 1 | ------ dt | 2 | 1 - t | / 0
Integral(1/(1 - t^2), (t, 0, 1))
PiecewiseRule(subfunctions=[(ArctanRule(a=1, b=-1, c=1, context=1/(1 - t**2), symbol=t), False), (ArccothRule(a=1, b=-1, c=1, context=1/(1 - t**2), symbol=t), t**2 > 1), (ArctanhRule(a=1, b=-1, c=1, context=1/(1 - t**2), symbol=t), t**2 < 1)], context=1/(1 - t**2), symbol=t)
Add the constant of integration:
The answer is:
/ | // 2 \ | 1 ||acoth(t) for t > 1| | ------ dt = C + |< | | 2 || 2 | | 1 - t \\atanh(t) for t < 1/ | /
pi*I
oo + ----
2
=
pi*I
oo + ----
2
oo + pi*i/2
Use the examples entering the upper and lower limits of integration.