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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of x*2^(-x)
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Integral of (1/x^2)dx
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Integral of x*cos(x/2)
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Integral of y^(-2/3)
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Identical expressions
- one /(one -e^(-2x))
- 1 divide by (1 minus e to the power of ( minus 2x))
- one divide by (one minus e to the power of ( minus 2x))
- 1/(1-e(-2x))
- 1/1-e-2x
- 1/1-e^-2x
- 1 divide by (1-e^(-2x))
- 1/(1-e^(-2x))dx
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Similar expressions
- 1/(1+e^(-2x))
- 1/(1-e^(2x))
Integral of 1/(1-e^(-2x)) dx
The solution
You have entered
[src]
1 / | | 1 | 1*--------- dx | -2*x | 1 - e | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{1 - e^{- 2 x}}\, dx$$
Integral(1/(1 - 1/E^(2*x)), (x, 0, 1))
The answer (Indefinite)
[src]
/ | / -2*x\ / -2*x\ | 1 log\-2 + 2*e / log\2*e / | 1*--------- dx = C + ----------------- - ------------ | -2*x 2 2 | 1 - e | /
$$\int 1 \cdot \frac{1}{1 - e^{- 2 x}}\, dx = C + \frac{\log{\left(-2 + 2 e^{- 2 x} \right)}}{2} - \frac{\log{\left(2 e^{- 2 x} \right)}}{2}$$
The answer
[src]
pi*I
oo + ----
2
$$\infty + \frac{i \pi}{2}$$
=
=
pi*I
oo + ----
2
$$\infty + \frac{i \pi}{2}$$
Use the examples entering the upper and lower limits of integration.