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Integral of 1/(1-cos(6*x)) dx

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The solution

You have entered [src]
  p                
  -                
  4                
  /                
 |                 
 |       1         
 |  ------------ dx
 |  1 - cos(6*x)   
 |                 
/                  
p                  
-                  
6                  
p6p411cos(6x)dx\int\limits_{\frac{p}{6}}^{\frac{p}{4}} \frac{1}{1 - \cos{\left(6 x \right)}}\, dx
Integral(1/(1 - cos(6*x)), (x, p/6, p/4))
Detail solution
  1. Rewrite the integrand:

    11cos(6x)=1cos(6x)1\frac{1}{1 - \cos{\left(6 x \right)}} = - \frac{1}{\cos{\left(6 x \right)} - 1}

  2. The integral of a constant times a function is the constant times the integral of the function:

    (1cos(6x)1)dx=1cos(6x)1dx\int \left(- \frac{1}{\cos{\left(6 x \right)} - 1}\right)\, dx = - \int \frac{1}{\cos{\left(6 x \right)} - 1}\, dx

    1. Don't know the steps in finding this integral.

      But the integral is

      16tan(3x)\frac{1}{6 \tan{\left(3 x \right)}}

    So, the result is: 16tan(3x)- \frac{1}{6 \tan{\left(3 x \right)}}

  3. Add the constant of integration:

    16tan(3x)+constant- \frac{1}{6 \tan{\left(3 x \right)}}+ \mathrm{constant}


The answer is:

16tan(3x)+constant- \frac{1}{6 \tan{\left(3 x \right)}}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                
 |                                 
 |      1                    1     
 | ------------ dx = C - ----------
 | 1 - cos(6*x)          6*tan(3*x)
 |                                 
/                                  
11cos(6x)dx=C16tan(3x)\int \frac{1}{1 - \cos{\left(6 x \right)}}\, dx = C - \frac{1}{6 \tan{\left(3 x \right)}}
The answer [src]
      1           1    
- ---------- + --------
       /3*p\        /p\
  6*tan|---|   6*tan|-|
       \ 4 /        \2/
16tan(3p4)+16tan(p2)- \frac{1}{6 \tan{\left(\frac{3 p}{4} \right)}} + \frac{1}{6 \tan{\left(\frac{p}{2} \right)}}
=
=
      1           1    
- ---------- + --------
       /3*p\        /p\
  6*tan|---|   6*tan|-|
       \ 4 /        \2/
16tan(3p4)+16tan(p2)- \frac{1}{6 \tan{\left(\frac{3 p}{4} \right)}} + \frac{1}{6 \tan{\left(\frac{p}{2} \right)}}
-1/(6*tan(3*p/4)) + 1/(6*tan(p/2))

    Use the examples entering the upper and lower limits of integration.