Integral of 1/4(x+1)^2 dx
The solution
Detail solution
-
The integral of a constant times a function is the constant times the integral of the function:
∫4(x+1)2dx=4∫(x+1)2dx
-
There are multiple ways to do this integral.
Method #1
-
Let u=x+1.
Then let du=dx and substitute du:
∫u2du
-
The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
Now substitute u back in:
3(x+1)3
Method #2
-
Rewrite the integrand:
(x+1)2=x2+2x+1
-
Integrate term-by-term:
-
The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
-
The integral of a constant times a function is the constant times the integral of the function:
∫2xdx=2∫xdx
-
The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: x2
-
The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 3x3+x2+x
So, the result is: 12(x+1)3
-
Now simplify:
12(x+1)3
-
Add the constant of integration:
12(x+1)3+constant
The answer is:
12(x+1)3+constant
The answer (Indefinite)
[src]
/
|
| 2 3
| (x + 1) (x + 1)
| -------- dx = C + --------
| 4 12
|
/
∫4(x+1)2dx=C+12(x+1)3
The graph
Use the examples entering the upper and lower limits of integration.