Integral of -y^2 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫(−y2)dy=−∫y2dy
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The integral of yn is n+1yn+1 when n=−1:
∫y2dy=3y3
So, the result is: −3y3
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Add the constant of integration:
−3y3+constant
The answer is:
−3y3+constant
The answer (Indefinite)
[src]
/
| 3
| 2 y
| -y dy = C - --
| 3
/
∫(−y2)dy=C−3y3
The graph
Use the examples entering the upper and lower limits of integration.