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Solving integrals/ -x^2-4x+5

Integral of -x^2-4x+5 dx

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The solution

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∫01((−x2−4x)+5) dx\int\limits_{0}^{1} \left(\left(- x^{2} - 4 x\right) + 5\right)\, dx 
Integral(-x^2 - 4*x + 5, (x, 0, 1))
Detail solution

  1. Integrate term-by-term:

    1. Integrate term-by-term:

      1. The integral of a constant times a function is the constant times the integral of the function:

        ∫(−x2) dx=−∫x2 dx\int \left(- x^{2}\right)\, dx = - \int x^{2}\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n≠−1n \neq -1:

          ∫x2 dx=x33\int x^{2}\, dx = \frac{x^{3}}{3}

        So, the result is: −x33- \frac{x^{3}}{3}

      1. The integral of a constant times a function is the constant times the integral of the function:

        ∫(−4x) dx=−4∫x dx\int \left(- 4 x\right)\, dx = - 4 \int x\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n≠−1n \neq -1:

          ∫x dx=x22\int x\, dx = \frac{x^{2}}{2}

        So, the result is: −2x2- 2 x^{2}

      The result is: −x33−2x2- \frac{x^{3}}{3} - 2 x^{2}

    1. The integral of a constant is the constant times the variable of integration:

      ∫5 dx=5x\int 5\, dx = 5 x

    The result is: −x33−2x2+5x- \frac{x^{3}}{3} - 2 x^{2} + 5 x

  2. Now simplify:

    x(−x2−6x+15)3\frac{x \left(- x^{2} - 6 x + 15\right)}{3}

  3. Add the constant of integration:

    x(−x2−6x+15)3+constant\frac{x \left(- x^{2} - 6 x + 15\right)}{3}+ \mathrm{constant}

The answer is:

x(−x2−6x+15)3+constant\frac{x \left(- x^{2} - 6 x + 15\right)}{3}+ \mathrm{constant}

The answer (Indefinite) [src] 
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 | \- x  - 4*x + 5/ dx = C - 2*x  + 5*x - --
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∫((−x2−4x)+5) dx=C−x33−2x2+5x\int \left(\left(- x^{2} - 4 x\right) + 5\right)\, dx = C - \frac{x^{3}}{3} - 2 x^{2} + 5 x
Simplify
The graph
0.001.000.100.200.300.400.500.600.700.800.90010
Plot the graph f(x)
The answer [src] 
8/3
83\frac{8}{3} 
=
= 
8/3
83\frac{8}{3} 
8/3
Numerical answer [src] 
2.66666666666667
2.66666666666667

    Use the examples entering the upper and lower limits of integration.

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