Integral of -x^3+3x-2 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x3)dx=−∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: −4x4
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The integral of a constant times a function is the constant times the integral of the function:
∫3xdx=3∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 23x2
The result is: −4x4+23x2
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The integral of a constant is the constant times the variable of integration:
∫(−2)dx=−2x
The result is: −4x4+23x2−2x
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Now simplify:
4x(−x3+6x−8)
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Add the constant of integration:
4x(−x3+6x−8)+constant
The answer is:
4x(−x3+6x−8)+constant
The answer (Indefinite)
[src]
/
| 4 2
| / 3 \ x 3*x
| \- x + 3*x - 2/ dx = C - 2*x - -- + ----
| 4 2
/
∫((−x3+3x)−2)dx=C−4x4+23x2−2x
The graph
Use the examples entering the upper and lower limits of integration.