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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 1/(x^2)-1
- Integral of 1/((x^2-1)(x-1))
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Integral of y/(1-y)
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Integral of x/(4x^2+1)
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Identical expressions
- ln((x- two)/(x+ two))
- ln((x minus 2) divide by (x plus 2))
- ln((x minus two) divide by (x plus two))
- lnx-2/x+2
- ln((x-2) divide by (x+2))
- ln((x-2)/(x+2))dx
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Similar expressions
- ln((x+2)/(x+2))
- ln((x-2)/(x-2))
Integral of ln((x-2)/(x+2)) dx
The solution
You have entered
[src]
1 / | | /x - 2\ | log|-----| dx | \x + 2/ | / 0
$$\int\limits_{0}^{1} \log{\left(\frac{x - 2}{x + 2} \right)}\, dx$$
Integral(log((x - 2)/(x + 2)), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | /x - 2\ /x - 2\ | log|-----| dx = C - 2*log(-2 + x) - 2*log(2 + x) + x*log|-----| | \x + 2/ \x + 2/ | /
$$\int \log{\left(\frac{x - 2}{x + 2} \right)}\, dx = C + x \log{\left(\frac{x - 2}{x + 2} \right)} - 2 \log{\left(x - 2 \right)} - 2 \log{\left(x + 2 \right)}$$
The graph
The answer
[src]
-3*log(3) + 2*log(4) + pi*I
$$- 3 \log{\left(3 \right)} + 2 \log{\left(4 \right)} + i \pi$$
=
=
-3*log(3) + 2*log(4) + pi*I
$$- 3 \log{\left(3 \right)} + 2 \log{\left(4 \right)} + i \pi$$
-3*log(3) + 2*log(4) + pi*i
Numerical answer
[src]
(-0.523248143764548 + 3.14159265358979j)
(-0.523248143764548 + 3.14159265358979j)
Use the examples entering the upper and lower limits of integration.