Integral of ln^3xdx/x dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Let u=log(x).
Then let du=xdx and substitute du:
∫u3du
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The integral of un is n+1un+1 when n=−1:
∫u3du=4u4
Now substitute u back in:
4log(x)4
Method #2
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Let u=x1.
Then let du=−x2dx and substitute −du:
∫ulog(u1)3du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−ulog(u1)3)du=−∫ulog(u1)3du
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Let u=log(u1).
Then let du=−udu and substitute −du:
∫u3du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−u3)du=−∫u3du
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The integral of un is n+1un+1 when n=−1:
∫u3du=4u4
So, the result is: −4u4
Now substitute u back in:
−4log(u1)4
So, the result is: 4log(u1)4
Now substitute u back in:
4log(x)4
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Add the constant of integration:
4log(x)4+constant
The answer is:
4log(x)4+constant
The answer (Indefinite)
[src]
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| 4
| 3 1 log (x)
| log (x)*1*- dx = C + -------
| x 4
|
/
4(logx)4
Use the examples entering the upper and lower limits of integration.