Integral of 4/(3x-1)^3 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫(3x−1)34dx=4∫(3x−1)31dx
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Don't know the steps in finding this integral.
But the integral is
−54x2−36x+61
So, the result is: −54x2−36x+64
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Now simplify:
−27x2−18x+32
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Add the constant of integration:
−27x2−18x+32+constant
The answer is:
−27x2−18x+32+constant
The answer (Indefinite)
[src]
/
|
| 4 4
| ---------- dx = C - ----------------
| 3 2
| (3*x - 1) 6 - 36*x + 54*x
|
/
−3(3x−1)22
The graph
Use the examples entering the upper and lower limits of integration.