Integral of 4/sqrt(x) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫x4dx=4∫x1dx
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Let u=x.
Then let du=2xdx and substitute 2du:
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: 2u
Now substitute u back in:
So, the result is: 8x
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Add the constant of integration:
8x+constant
The answer is:
8x+constant
The answer (Indefinite)
[src]
/
|
| 4 ___
| ----- dx = C + 8*\/ x
| ___
| \/ x
|
/
∫x4dx=C+8x
Use the examples entering the upper and lower limits of integration.