Integral of 8-2x^2 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫8dx=8x
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The integral of a constant times a function is the constant times the integral of the function:
∫(−2x2)dx=−∫2x2dx
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The integral of a constant times a function is the constant times the integral of the function:
∫2x2dx=2∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: 32x3
So, the result is: −32x3
The result is: −32x3+8x
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Now simplify:
32x(12−x2)
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Add the constant of integration:
32x(12−x2)+constant
The answer is:
32x(12−x2)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2\ 2*x
| \8 - 2*x / dx = C + 8*x - ----
| 3
/
8x−32x3
The graph
Use the examples entering the upper and lower limits of integration.