Integral of e^x*dx*dx/(e^(2*x)+1) dx
The solution
The answer (Indefinite)
[src]
/
|
| x
| E / x\
| -------- dx = C + atan\E /
| 2*x
| E + 1
|
/
$$\int \frac{e^{x}}{e^{2 x} + 1}\, dx = C + \operatorname{atan}{\left(e^{x} \right)}$$
/ 2 \ / 2 \
- RootSum\4*z + 1, i -> i*log(1 + 2*i)/ + RootSum\4*z + 1, i -> i*log(E + 2*i)/
$$- \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + 1 \right)} \right)\right)} + \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + e \right)} \right)\right)}$$
=
/ 2 \ / 2 \
- RootSum\4*z + 1, i -> i*log(1 + 2*i)/ + RootSum\4*z + 1, i -> i*log(E + 2*i)/
$$- \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + 1 \right)} \right)\right)} + \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + e \right)} \right)\right)}$$
-RootSum(4*_z^2 + 1, Lambda(_i, _i*log(1 + 2*_i))) + RootSum(4*_z^2 + 1, Lambda(_i, _i*log(E + 2*_i)))
Use the examples entering the upper and lower limits of integration.