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- Improper integral
- Double Integral
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- Derivative Step by Step
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How to use it?
- Integral of d{x}:
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Integral of 1/sqrt(1-x)
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Integral of (x^2)^(1/3)
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Integral of (x+3)
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Integral of (x+1)dx
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Identical expressions
- dx/((x^ two)-7x- eight)
- dx divide by ((x squared ) minus 7x minus 8)
- dx divide by ((x to the power of two) minus 7x minus eight)
- dx/((x2)-7x-8)
- dx/x2-7x-8
- dx/((x²)-7x-8)
- dx/((x to the power of 2)-7x-8)
- dx/x^2-7x-8
- dx divide by ((x^2)-7x-8)
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Similar expressions
- dx/((x^2)+7x-8)
- dx/((x^2)-7x+8)
Integral of dx/((x^2)-7x-8) dx
The solution
You have entered
[src]
1 / | | 1 | 1*------------ dx | 2 | x - 7*x - 8 | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{x^{2} - 7 x - 8}\, dx$$
Integral(1/(x^2 - 7*x - 1*8), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 log(2 + 2*x) log(-16 + 2*x) | 1*------------ dx = C - ------------ + -------------- | 2 9 9 | x - 7*x - 8 | /
$$\int 1 \cdot \frac{1}{x^{2} - 7 x - 8}\, dx = C + \frac{\log{\left(2 x - 16 \right)}}{9} - \frac{\log{\left(2 x + 2 \right)}}{9}$$
The graph
The answer
[src]
log(2) log(8) log(7)
- ------ - ------ + ------
9 9 9
$$- \frac{\log{\left(8 \right)}}{9} - \frac{\log{\left(2 \right)}}{9} + \frac{\log{\left(7 \right)}}{9}$$
=
=
log(2) log(8) log(7)
- ------ - ------ + ------
9 9 9
$$- \frac{\log{\left(8 \right)}}{9} - \frac{\log{\left(2 \right)}}{9} + \frac{\log{\left(7 \right)}}{9}$$
The graph
Use the examples entering the upper and lower limits of integration.