Integral of dx/xlog^2(x) dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Let u=x1.
Then let du=−x2dx and substitute −du:
∫(−ulog(u1)2)du
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The integral of a constant times a function is the constant times the integral of the function:
∫ulog(u1)2du=−∫ulog(u1)2du
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Let u=log(u1).
Then let du=−udu and substitute −du:
∫(−u2)du
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The integral of a constant times a function is the constant times the integral of the function:
∫u2du=−∫u2du
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: −3u3
Now substitute u back in:
−3log(u1)3
So, the result is: 3log(u1)3
Now substitute u back in:
3log(x)3
Method #2
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Let u=log(x).
Then let du=xdx and substitute du:
∫u2du
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
Now substitute u back in:
3log(x)3
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Add the constant of integration:
3log(x)3+constant
The answer is:
3log(x)3+constant
The answer (Indefinite)
[src]
/
|
| 2 3
| log (x) log (x)
| ------- dx = C + -------
| x 3
|
/
∫xlog(x)2dx=C+3log(x)3
Use the examples entering the upper and lower limits of integration.