Integral of dx/(2*x+3) dx

The solution

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  1           
  /           
 |            
 |     1      
 |  ------- dx
 |  2*x + 3   
 |            
/             
1

$$\int\limits_{1}^{1} \frac{1}{2 x + 3}\, dx$$

Integral(1/(2*x + 3), (x, 1, 1))

Detail solution

Let $u = 2 x + 3$ .

Then let $du = 2 dx$ and substitute $\frac{du}{2}$ :

$\int \frac{1}{2 u}\, du$
1. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int \frac{1}{u}\, du = \frac{\int \frac{1}{u}\, du}{2}$
  1. The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
  So, the result is: $\frac{\log{\left(u \right)}}{2}$
Now substitute $u$ back in:

$\frac{\log{\left(2 x + 3 \right)}}{2}$
Now simplify:

$\frac{\log{\left(2 x + 3 \right)}}{2}$
Add the constant of integration:

$\frac{\log{\left(2 x + 3 \right)}}{2}+ \mathrm{constant}$

The answer is:

$\frac{\log{\left(2 x + 3 \right)}}{2}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                             
 |                              
 |    1             log(2*x + 3)
 | ------- dx = C + ------------
 | 2*x + 3               2      
 |                              
/

$$\int \frac{1}{2 x + 3}\, dx = C + \frac{\log{\left(2 x + 3 \right)}}{2}$$

Simplify

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The answer [src]

$$0$$

Numerical answer [src]

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0.0

Use the examples entering the upper and lower limits of integration.

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Integral of dx/(2*x+3) dx

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