Integral of dx/sqrt(1-2x) dx
The solution
Detail solution
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Let u=1−2x.
Then let du=−1−2xdx and substitute −du:
∫(−1)du
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: −u
Now substitute u back in:
−1−2x
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Add the constant of integration:
−1−2x+constant
The answer is:
−1−2x+constant
The answer (Indefinite)
[src]
/
|
| 1 _________
| ----------- dx = C - \/ 1 - 2*x
| _________
| \/ 1 - 2*x
|
/
∫1−2x1dx=C−1−2x
The graph
(0.0 - 0.999999999734761j)
(0.0 - 0.999999999734761j)
Use the examples entering the upper and lower limits of integration.