1 / | | x | cos (1) dx | / 0
Integral(cos(1)^x, (x, 0, 1))
The integral of an exponential function is itself divided by the natural logarithm of the base.
Add the constant of integration:
The answer is:
/ | x | x cos (1) | cos (1) dx = C + ----------- | log(cos(1)) /
1 cos(1) - ----------- + ----------- log(cos(1)) log(cos(1))
=
1 cos(1) - ----------- + ----------- log(cos(1)) log(cos(1))
-1/log(cos(1)) + cos(1)/log(cos(1))
Use the examples entering the upper and lower limits of integration.