Integral of (7x-5)*x-2dx*(1/3) dx
The solution
Detail solution
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Integrate term-by-term:
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Rewrite the integrand:
x(7x−5)=7x2−5x
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫7x2dx=7∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: 37x3
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The integral of a constant times a function is the constant times the integral of the function:
∫(−5x)dx=−5∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −25x2
The result is: 37x3−25x2
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The integral of a constant is the constant times the variable of integration:
∫3(−1)2dx=−32x
The result is: 37x3−25x2−32x
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Now simplify:
6x(14x2−15x−4)
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Add the constant of integration:
6x(14x2−15x−4)+constant
The answer is:
6x(14x2−15x−4)+constant
The answer (Indefinite)
[src]
/
| 2 3
| / 2*(-1)\ 5*x 2*x 7*x
| |(7*x - 5)*x + ------| dx = C - ---- - --- + ----
| \ 3 / 2 3 3
|
/
∫(x(7x−5)+3(−1)2)dx=C+37x3−25x2−32x
The graph
−3118
=
−3118
Use the examples entering the upper and lower limits of integration.