Integral of (5x^4+2x-1)*dx dx

1. Integrate term-by-term:

   1. Integrate term-by-term:

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 5 x^{4}\, dx = 5 \int x^{4}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{4}\, dx = \frac{x^{5}}{5}$$

         So, the result is: $x^{5}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 2 x\, dx = 2 \int x\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x\, dx = \frac{x^{2}}{2}$$

         So, the result is: $x^{2}$

      The result is: $x^{5} + x^{2}$

   1. The integral of a constant is the constant times the variable of integration:

      $$\int \left(-1\right)\, dx = - x$$

   The result is: $x^{5} + x^{2} - x$

2. Now simplify:

   $$x \left(x^{4} + x - 1\right)$$

3. Add the constant of integration:

   $$x \left(x^{4} + x - 1\right)+ \mathrm{constant}$$

The answer is:

$$x \left(x^{4} + x - 1\right)+ \mathrm{constant}$$