Integral of (4x^3-2x) dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫4x3dx=4∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: x4
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The integral of a constant times a function is the constant times the integral of the function:
∫(−2x)dx=−2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −x2
The result is: x4−x2
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Add the constant of integration:
x4−x2+constant
The answer is:
x4−x2+constant
The answer (Indefinite)
[src]
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| / 3 \ 4 2
| \4*x - 2*x/ dx = C + x - x
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/
∫(4x3−2x)dx=C+x4−x2
The graph
Use the examples entering the upper and lower limits of integration.