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(4sinx+2cosx)dx.
Solving integrals/ (4sinx+2cosx)dx.

Integral of (4sinx+2cosx)dx. dx

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The solution

You have entered [src] 
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 |  (4*sin(x) + 2*cos(x))*1 dx
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∫01(4sin⁡(x)+2cos⁡(x))1 dx\int\limits_{0}^{1} \left(4 \sin{\left(x \right)} + 2 \cos{\left(x \right)}\right) 1\, dx
Simplify
The answer (Indefinite) [src] 
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 | (4*sin(x) + 2*cos(x))*1 dx = C - 4*cos(x) + 2*sin(x)
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2 sin⁡x−4 cos⁡x2\,\sin x-4\,\cos x
Simplify
The graph
0.001.000.100.200.300.400.500.600.700.800.90-1010
Plot the graph f(x)
The answer [src] 
4 - 4*cos(1) + 2*sin(1)
2 sin⁡1−4 cos⁡1+42\,\sin 1-4\,\cos 1+4 
=
= 
4 - 4*cos(1) + 2*sin(1)
−4cos⁡(1)+2sin⁡(1)+4- 4 \cos{\left(1 \right)} + 2 \sin{\left(1 \right)} + 4
Simplify
Numerical answer [src] 
3.52173274614323
3.52173274614323
The graph
Integral of (4sinx+2cosx)dx. dx

    Use the examples entering the upper and lower limits of integration.

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