Integral of 3x^4dx dx

1. The integral of a constant times a function is the constant times the integral of the function:

   $$\int 3 x^{4} \cdot 1\, dx = 3 \int x^{4}\, dx$$

   1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

      $$\int x^{4}\, dx = \frac{x^{5}}{5}$$

   So, the result is: $\frac{3 x^{5}}{5}$

2. Add the constant of integration:

   $$\frac{3 x^{5}}{5}+ \mathrm{constant}$$

The answer is:

$$\frac{3 x^{5}}{5}+ \mathrm{constant}$$